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Regular expression [Any number]

I need to test for "[any number]" in a string in javascript. how would i match it?

Oh, "[" and "]" also need to be matched.

so string like "[1]" or "[12345]" is a match.

Non match: "[23432" or "1]"

So for example:

$('.form .section .parent').find('input.text').each(function(index){
      $(this).attr("name", $(this).attr("name").replace("[current]", "['"+index+"']"));
});

I need to replace input fields name: "items[0].firstname" to "items[1].firstname" thanks

over 4 years ago · Santiago Trujillo
3 answers
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0

UPDATE: for your updated question

variable.match(/\[[0-9]+\]/);

Try this:

variable.match(/[0-9]+/);    // for unsigned integers
variable.match(/[-0-9]+/);   // for signed integers
variable.match(/[-.0-9]+/);  // for signed float numbers

Hope this helps!

over 4 years ago · Santiago Trujillo Report

0

if("123".search(/^\d+$/) >= 0){
   // its a number
}
over 4 years ago · Santiago Trujillo Report

0

I always use the following regular expression to detect any kind of number in a string. Had no issues so far.

'(([\+\-]*\d*\.*\d+[eE])?([\+\-]*\d*\.*\d+))'

In detail:

'([\+\-]*\d*\.*\d+)'

to match a (non-)decimal number with(out) leading digits or sign

'([\+\-]*\d*\.*\d+[eE])?'

to match an exponential base before the number.

If there are brackets around required, you can add them inside or outside of the surrounding paranthesis:

'(\[([\+\-]*\d*\.*\d+[eE])?([\+\-]*\d*\.*\d+)\])'

In fact the surrounding paranthesis are not necessary, but i keep them to easier concatenate the expression with others.

over 4 years ago · Santiago Trujillo Report
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